Chemistry, asked by Korangadevs2154, 11 months ago

Solid nh4i dissociates according to the equation

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Answered by Anonymous
6

Explanation:

Solid NH4I dissociates according to the reaction at 400 K NH4I(s) NH3(g) + HI(g) ; Kp = 16 atm. If partial pressure of H2 at this temp is 1 atm in the container when both the equilibrium exist simultaneously, calculate Kp value of second equilibrium (for the dissociation of HI).

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