Question

Solid sphere of diameter6 cm are dropped into a cylindrical beaker containg some water and are fully submerged.if the diameter of the beaker is 18cm and the water rises by 40cm in the beaker,find the no.ofsolid sphere dropped in the water

Answer 1

Answer:

Step-by-step explanation:

Let the number of solid spheres be x.

Given diameter of solid sphere = 6 cm

Hence radius of the solid sphere = 3 cm

Volume of solid sphere cubic units

cubic cm

Therefore volume of x solid spheres

Given beaker is in the shape of a cylinder with diameter 18 cm

Radius of beaker, r = 9 cm

Let the height of water before the solid spheres are dropped be h cm

Volume of water =

Total volume = Volume of water + volume of x solid spheres

→ (1)

After the solid spheres are dropped in the beaker, the height of water increased by 40 cm

Hence the final height of water = (h + 40) cm

Radius of the beaker = 9 cm

Total Volume =

Hence equation (1) becomes,

Thus there are 90 solid spheres that are dropped in to the beaker.

Answer 2

take no of solid sphere = n
answer is n= 90