Question

solubility of aqueous solution of NaCl at 30°C is 40. if 350gm of its satuarated solution is heated to dryness how much salt is left behind​

Answer 1

Answer:

weight of salt = 90 gram,  

solubility  = 50

sing formula  

solubility of solute =  weightofsoluteinsaturatedsolution /weightofsolventinsaturatedsolution  ×100

or 50=  90gm /weightofsolventinsaturatedsolutio ×100

so weight of solvent in saturated solution = 90gm /50 ×100=180gm

Hence 180 gm of water is required to prepare a saturated solution.