Question

Solubility of CaF2 is 3.5×10^-4/mol. Calculate the solubility product

Answer 1

Answer:

Refer attachment!!!

Answer 2

Given:

The solubility of CaF2, s = 3.5 × 10⁻⁴ mol⁻¹

To Find:

The solubility product for CaF2 in the given reaction.

Calculation:

- The reaction can be denoted as follows:

CaF2 ⇄ Ca²⁺  +  2 F⁻

               s          (2s)²

- The solubility product for the following reaction is given as:

K$_{sp}$ = s × (2s)²

⇒ K$_{sp}$ = 4s³

⇒ K$_{sp}$ = 4 × (3.5 × 10⁻⁴)³

⇒ K$_{sp}$ = 171.5 × 10⁻¹²

⇒ K$_{sp}$ = 1.715 × 10⁻¹⁰ M³

- So, the solubility product for CaF2 in the given reaction is 1.715 × 10⁻¹⁰ M³.