Chemistry, asked by chitragodiwala1, 3 months ago

Solubility product of BaSO4 is 1.1 × 10–10. Calculate the volume of its solution containing 15 mg salt in the

solution.​

Answers

Answered by yokeshps2005
0

Answer:

the above attached one is similiar one

Attachments:
Answered by sahilmeena030
0

Answer:

BaSO

4

(s)⟶Ba

2+

(aq)+SO

4

2−

(aq)

∴K

sp

=[Ba

2+

][SO

4

2−

]=x

Then, 1.5×10

−9

=x×x;x

2

=15×10

−10

or3.87×10

−5

Then, solubility of BaSO

4

in pure water is 3.87×10

−5

.

Let the solubility of BaSO

4

in 0.1MBaCl

2

be

s

Allsolid

BaSO

4

(s)

0.1M

Ba

2+

(aq)

+SO

4

(aq)

Initial (from BaCl

2

) 0

At equilibrium (0.1M+s) s

Hence, 1.5×10

−9

=(s+0.1)×s=s×0.1(Since s<<1)

s=1.5×10

−8

Thus the solubility of BaSO

4

in presence of 0.1M BaCl

2

is 1.5×10

−8

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