Math, asked by indubabbar38, 8 days ago

Solue for a²b²x²+ b²x - a ²x-1=0​

Answers

Answered by ironmancaptain65
0

Answer:

\begin{gathered}a^2b^2x^2+b^2x-a^2x-1=0 \\ \\ \implies b^2x(a^2x+1)-1(a^2x+1) = 0 \\ \\ \implies (a^2x+1)(b^2x-1)=0\\ \\ \implies a^2x+1=0 \,\, or \, \, b^2x-1=0 \\ \\ \implies \boxed{x=-\frac{1}{a^2}} \, \, or \, \, \boxed{x=\frac{1}{b^2}}\end{gathered}

a

2

b

2

x

2

+b

2

x−a

2

x−1=0

⟹b

2

x(a

2

x+1)−1(a

2

x+1)=0

⟹(a

2

x+1)(b

2

x−1)=0

⟹a

2

x+1=0orb

2

x−1=0

x=−

a

2

1

or

x=

b

2

1

Answered by harpreetthind1981
0

Answer:

hhhhhhhhhhhhhhhhhhhhhhhhhhh

Similar questions