Solue for a²b²x²+ b²x - a ²x-1=0
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Answer:
\begin{gathered}a^2b^2x^2+b^2x-a^2x-1=0 \\ \\ \implies b^2x(a^2x+1)-1(a^2x+1) = 0 \\ \\ \implies (a^2x+1)(b^2x-1)=0\\ \\ \implies a^2x+1=0 \,\, or \, \, b^2x-1=0 \\ \\ \implies \boxed{x=-\frac{1}{a^2}} \, \, or \, \, \boxed{x=\frac{1}{b^2}}\end{gathered}
a
2
b
2
x
2
+b
2
x−a
2
x−1=0
⟹b
2
x(a
2
x+1)−1(a
2
x+1)=0
⟹(a
2
x+1)(b
2
x−1)=0
⟹a
2
x+1=0orb
2
x−1=0
⟹
x=−
a
2
1
or
x=
b
2
1
Answered by
0
Answer:
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