Question

solue
the equation
2² +/z/zo,
where z is a
complex number​

Answer 1

Answer:

Z= x+iy

Z²= (x+iy)²= x²+2ixy +y²

|Z|=√(x²+y²)

Z²+|Z|=0

or, {x²+y²+√(x²+y²)} + 2ixy=0

x²+y²+√(x²+y²)=0 & 2xy= 0

so, if x=0 then y=0 or -1

if y= 0 then x=0 or -1