Question

Solue the following differential equation
dy/dx =
$\sqrt{1 - y {}^{2} } \div \sqrt{1 - x {}^{2} }$
​

Answer 1

Answer:

$\frac{dy}{dx} = \frac{ \sqrt{1 - {y}^{2} } }{ \sqrt{1 - {x}^{2} } }$

$\frac{dy}{ \sqrt{1 - {y}^{2} } } = \frac{dx}{ \sqrt{1 - {x}^{2} } }$

Integrating both sides, we get

$\sin {}^{ - 1} (y) = \sin {}^{ - 1} (x) + c$

Ans.

mark BRAINLIEST if this is helpful to you. Thanks