solution containing NaHCO3 and Na2CO3 was treated with excess of CaCl2 solution and filtered. m1 g of precipitate was obtained. On adding NaOH drop by drop, a further m2 g was precipitated. If after addition of CaCl2, the solution was not filtered but was boiled and filtered, what would have been the total weight of the precipitate?
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Usain keen owen Irwin mac
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