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In /\ AOB AND AOD
/_AOB =/_AOD. . . . . (Each angle is 90°)
OA=OA. . . . . . . . (COMMON)
OB= OD. . . . . . . (PERPENDICULER TO A)
HENCE PROVE AB=AD
SIMMILERLY
. . . . . BC=DC
/_AOB =/_AOD. . . . . (Each angle is 90°)
OA=OA. . . . . . . . (COMMON)
OB= OD. . . . . . . (PERPENDICULER TO A)
HENCE PROVE AB=AD
SIMMILERLY
. . . . . BC=DC
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