solution for 2x+3y=8 , 4x +5y+14=0 by elimination , cross multiplication,substitution
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Solution.,
2x+3y=8
x=8-3y/2......(1)...
4x+5y+14=0
x=-14-5y/4........(2).....
From EQN....1 ...AND ....2...,WE GOT,
8-3y/2=-14-5y/4
8-3y=-14-5y/2
16-6y=-14-5y
-6y+5y=-14-16
-y=-30
y=30
Substitute the value of y in EQN..1...
x=8-3y/2
x=8-3×30/2
x=8-90/2
x=4-45
x=-41
{ x = -41 AND y = 30 }. Answer.........
IT WILL HELP YOU A LOT !
@ujjwalusri
2x+3y=8
x=8-3y/2......(1)...
4x+5y+14=0
x=-14-5y/4........(2).....
From EQN....1 ...AND ....2...,WE GOT,
8-3y/2=-14-5y/4
8-3y=-14-5y/2
16-6y=-14-5y
-6y+5y=-14-16
-y=-30
y=30
Substitute the value of y in EQN..1...
x=8-3y/2
x=8-3×30/2
x=8-90/2
x=4-45
x=-41
{ x = -41 AND y = 30 }. Answer.........
IT WILL HELP YOU A LOT !
@ujjwalusri
alekhyakasi2853:
thank u so much
if you like my ans, then MARK AS BRAINLIST....
y=5 no
where did 6 go .....
Now see,there is gently mistake,now I correct it.
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