Math, asked by alekhyakasi2853, 1 year ago

solution for 2x+3y=8 , 4x +5y+14=0 by elimination , cross multiplication,substitution

Answers

Answered by ujjwalusri

Solution.,
2x+3y=8
x=8-3y/2......(1)...
4x+5y+14=0
x=-14-5y/4........(2).....

From EQN....1 ...AND ....2...,WE GOT,
8-3y/2=-14-5y/4
8-3y=-14-5y/2
16-6y=-14-5y
-6y+5y=-14-16
-y=-30
y=30

Substitute the value of y in EQN..1...
x=8-3y/2
x=8-3×30/2
x=8-90/2
x=4-45
x=-41

{ x = -41 AND y = 30 }. Answer.........
IT WILL HELP YOU A LOT !
@ujjwalusri

alekhyakasi2853: thank u so much

ujjwalusri: if you like my ans, then MARK AS BRAINLIST....

alekhyakasi2853: y=5 no

alekhyakasi2853: where did 6 go .....

ujjwalusri: Now see,there is gently mistake,now I correct it.

Answered by arshdeep997

Answer:

$\pi123 \\$

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