Question

Solution for: 3+√7/3-√7.

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!}}}$

$\frac{3 + \sqrt{7} }{3 - \sqrt{7} } \\ = \frac{3 + \sqrt{7} }{3 - \sqrt{7} } \times \frac{3 + \sqrt{7} }{3 + \sqrt{7} } \\ = \frac{3(3 + \sqrt{7}) + \sqrt{7} (3 + \sqrt{7} )}{3 {}^{2} - ( \sqrt{7}) {}^{2} } \\ = \frac{9 + 3 \sqrt{7} + 3 \sqrt{7} + 7 }{9 - 7} \\ = \frac{16 + 6 \sqrt{7} }{2} \\ = \frac{16}{2} + \frac{6 \sqrt{7} }{2} \\ = 8 + 3 \sqrt{7}$


$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{Hope\:it\:helps\: you}}}}}}}}}}}}}}$