solution for q5. ans is [(x-3)^2 - 1]
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The answer is given below :
Given that,
f(x + 3) = x² - 1
To find f(x), we replace x by (x - 3).
Then, we get
f(x - 3 + 3) = (x - 3)² - 1
⇒ f(x) = x² - 6x + 9 - 1,
using the identity (a - b)² = a² - 2ab + b²
⇒ f(x) = x² - 6x + 8
Thus, f(x) = x² - 6x + 8
Thank you for your question.
Given that,
f(x + 3) = x² - 1
To find f(x), we replace x by (x - 3).
Then, we get
f(x - 3 + 3) = (x - 3)² - 1
⇒ f(x) = x² - 6x + 9 - 1,
using the identity (a - b)² = a² - 2ab + b²
⇒ f(x) = x² - 6x + 8
Thus, f(x) = x² - 6x + 8
Thank you for your question.
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