Solution of 2/x+3/y=13 and 5/x-4/y=-2
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Let 1/x be u and 1/y be v.
Then, 2u + 3v = 13 __(1)
and, 5u - 4v = - 2 __(2)
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By multiplying 5 × (1) and 2 × (5),
→ 10u + 15v = 65 __(3)
→ 10u - 8v = - 4 __(4)
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By subtracting (3) by (4),
→ 23v = 69
→ v = 3
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By susbtituting value of v in (1),
→ 2u + 3v = 13
→ 2u + 3(3) = 13
→ u = 4/2
→ u = 2
Therefore x = 1/2 and y = 1/3.
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