Question

Solution of equation x²-4x-192 = 0

Answer 1

Given equation is x^2 - 4x - 192 = 0.

                              x^2 - 16x + 12x - 192 = 0

                              x(x - 16) + 12(x - 16) = 0
 
                              (x - 16)(x + 12) = 0

                              x = 16,-12.


Therefore the solutions are x = 16 and x = -12.


Hope this helps!
                              

Answer 2

x²-4x-192 = 0
or x²-4x = 0+192
or x²-4x = 192
or x²-x = 192/4
or x²-x = 48
or x-x = √48
or x-x ≈6.93
or 0 ≈ 6.93