Solution of numrical a lift is going upwards with acceleration of 4.9m/s*s .what will be the apparent weight of a 60kg man in lift?what when the lift rises up with a uniform velocity of 4.9m/s*s?
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Normal force =MA +Mg
=60*4.9+60*9.8
=294+588
=882 Newton
The apparent weight of man will be 882 Newton
=60*4.9+60*9.8
=294+588
=882 Newton
The apparent weight of man will be 882 Newton
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