Question

solution of pardeep of class 9​

Answer 1

hope this will help you

Answer 2

Ray BO is the bisector of angle CBE

•°• angle CBO= 1/2angle CBE

= 1/2(180°- y)

=90°- y/2 ........ (1)

Similarly, ray CO is the bisector of angle BcD.

•°•angle BCO = 1/2 angle BCD

=1/2 (180°- z)

=90°-z /2

In triangle BOC,angle BOC, angleBCO +angleCBO=180°

substituting(1) and (2) in (3), you get

=angle BOC+90 °- z/2+90 °-y/2=180°

=angle BOC=z/2+y/2

=angle BOC=1/2 (y+z)

x +y +z =180°(Angle sum property of a triangle)

•°•y+z=180°-x

•°•(4) becomes

angle BOC=1/2 (180°-x)

=90 °- x/2

= =90 °- 1/2 angle BAC

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