Solution of x-y+1=0 and 3x+2y-12=0
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let equation 1 be x-y+1=0
and equation 2 be 3x+2y-12=0
multiplying eq.1 with 3 we get
3x-3y+3=0
and solving 1 and 2 we get,
3x-3y+3=0
3x+2y-12=0
-5y=-15
y=3
substituting in eq 2 we get
x=2
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