Question

solution should be done on a copy​

Answer 1

Answer:

answer Is option b ......

Answer 2

∛(x³ - 3x²  + 3x  - 1)= 0.0539  if x = 1.0539

Step-by-step explanation:

x = 1.0539

$\sqrt[3]{x^{3} -3x^{2} +3x - 1} \\ \\ =\sqrt[3]{x^{3} -3x^{2}\times1 +3x\times1^2 - 1^3}\\ \\ =\sqrt[3]{x^{3} + (-1)^3 +3x^{2}\times(-1) +3x\times(-1)^2}$

now using (a + b)³ = a³ + b³  + 3a²b + 3ab²

a = x   b = - 1

= ∛(x - 1)³

= x - 1

= 1.0539 - 1

= 0.0539

$\sqrt[3]{x^{3} -3x^{2} +3x - 1} = 0.0539$

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