Question

solution
xsquare+x-(a+1)(a+2)=0 are​

Answer 1

Answer:

x = a+1 or x = -(a+2)

Explanation:

x²+x-(a+1)(a+2)=0

Splitting the middle term,we get

=>x²-(a+1)x+(a+2)x-(a+1)(a+2)=0

=> x[x-(a+1]+(a+2)[x-(a+1)]=0

=>[x-(a+1)][x+(a+2)]=0

=> x-(a+1)=0 or x+(a+2)=0

=> x = a+1 or x = -(a+2)

••••

Answer 2

$\bf\huge\textbf{\underline{\underline{According\:to\:the\:Question}}}$  

x² + x - (a + 1)(a + 2) = 0

Now

Factorize it in meaningful manner we get

⇒ x²- (a + 1)x + (a + 2)x - (a + 1)(a + 2) = 0

⇒ x[x - (a + 1] + (a + 2)[x - (a + 1)] = 0

⇒ [x - (a + 1)][x + (a + 2)] = 0

⇒ x - (a + 1) = 0

⇒ x + (a + 2) = 0

⇒ x = a + 1  

⇒ x = -(a + 2)

$\bf\huge\bf\huge{\boxed{\bigstar{{x = a + 1\:and\: x = -(a + 2)}}}}$