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given,
BA || ED
and
BC || ED.
extrapolate the lines, EF and ED.
then, it forms parallelogram AEDB
the opposite angles are equal in a parallelogram.
hence angle ABC= angle AED.
angle AED + angle DEF= 180°.
Therefore,
angle ABC+angle DEF = 180°.
BA || ED
and
BC || ED.
extrapolate the lines, EF and ED.
then, it forms parallelogram AEDB
the opposite angles are equal in a parallelogram.
hence angle ABC= angle AED.
angle AED + angle DEF= 180°.
Therefore,
angle ABC+angle DEF = 180°.
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