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BOC =120'
POQ=90'
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POQ=90'
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nagunayak888:
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<AOC = 60° ---------- 1
& OQ is bisector of <AOC
=> <AOQ = <QOC = <AOC/2 = 30° -------- 2
NOW
<AOB is a straight angle
=> <AOB = 180° ---------- 3
(I) <BOC = <AOB - <AOC
= 180° - 60° (from 3 & 1)
=> <BOC = 120°
NOW
OP is the bisector of <BOC
=> <BOP = <POC = <BOC/2 = 60° ---------- 4
(ii) <POQ = <AOB - <BOP - <AOQ
= 180° - 60° - 30° (from 3, 4 & 2)
=> <POQ = 90°
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