Question

SOLUTIONS OF X^2+3X+2=0 (MOD 5) IS ? A. 1,3 B. 2,3 C. 2 D. DOES NOT EXISTS

Answer 1

Step-by-step explanation:

p(x)=x²+3x+2

First Find its Zeroes

p(x)=x²+2x+x+2

=x(x+2)+1(x+2)

=(x+1)(x+2)

x=-1,-2

p(-1)=0

0(mod5)=0

p(-2)=0

0(mod)5=0

So no solutions

Answer 2

Solutions of $x^2+3x+2=0(MOD5)$ is Does not exist

Step-by-step explanation:

Given:$x^2+3x+2=0(MOD5)$

To Find:Solutions of the equation $x^2+3x+2=0(MOD5)$  

Concept/Formula used:Finding roots of the equation by Middle term split

$x^2+3x+2=0(MOD5)$

The above equation is of the form $ax^2+bx+c=0$

So, now by Middle term split, solving LHS

$x^2+2x+x+2=0(MOD5)$

$x(x+2)+1(x+2)=0(MOD5)$

RHS$=0(MOD5)=0$

$x(x+2)+1(x+2)=0$

So, roots of the equation are

$x=-1;x=-2$

Hence, Solutions of the equation $x^2+3x+2=0(MOD5)$ does not exist