Question

solv no. 4 fast of rs agrawal​

Answer 1

Step-by-step explanation:

We have,

$ad^{2} ( \frac{ax}{b} + \frac{2c}{d} )x + b {c}^{2} = 0$

$\implies \:\frac{a^{2} {d}^{2} x ^{2} }{b} + 2acdx + b {c}^{2} = 0$

$\implies a^{2} {d}^{2} x ^{2} + 2abcdx + b ^{2} {c}^{2} = 0$

$\implies (adx + bc )^{2} = 0$

$\implies adx + bc = 0$

$\implies x = - \frac{bc}{ad}$