Question

Solve...
(01) x(3x^2- 19) = 2(x^2 - 11)
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Answer 1

Answer:

Let's solve your equation step-by-step.

x(3x²−19)=2(x²−11)

3x³−19x=2x²−22

Step 1: Subtract 2x²-22 from both sides.

3x³−19x−(2x²−22)=2x²−22−(2x²−22)

3x³−2x²−19x+22=0

Step 2: Factor left side of equation.

(x−2)(3x²+4x−11)=0

Step 3: Set factors equal to 0.

x−2=0 or 3x²+4x−11=0

x=2 or x=1.3609208434327398 or x=−2.694254176766073

Answer:

x=2 or x=1.3609208434327398 or x=−2.694254176766073

Answer 2

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