Question

Solve:


1. 3(t-3) = 5(2t+1).

2. z/(z+15) = 4/9.

3. A positive number is 5 times another number. If 21 is added to both the numbers, the one of the new number becomes twice the other new number.

What are the numbers?

4. The sum of three consecutive multiple of 8 is 888. Find the multiples.

plz give me the correct answer​

Answer 1

Answer:

1. -

2. -

3. A positive number is 5 times another number. If 21 is added to both the numbers, then one of the new numbers becomes twice the other new number. What are the numbers? Thus, the required numbers are 7 and 35.

4. Also the third consecutive multiple of 8 will be 8(x+2). => x = 36. If we sumup these three multiples i.e (288 + 296 + 304) we get 888.

Step-by-step explanation:

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