Question

solve 1/4x - 5/3 = 2x-4​

Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \large \: \dfrac{1}{4} x - \dfrac{5}{3} = 2x - 4$

$\sf \longmapsto \dfrac{x}{4} - \dfrac{5}{3} = 2x - 4$

Now, we take LCM of 4 and 3

4=2×2

3=1×3

LCM of 4 & 3=12

$\sf \longmapsto \dfrac{3x - 4 \times 5}{12} = 2x - 4$

$\sf \longmapsto \dfrac{3x - 20}{12} = 2x - 4$

Now,cross multiply to both sides

$\sf \longmapsto3x - 20 = 12(2x - 4)$

Now, expanding the terms

$\sf \longmapsto3x - 20 = 24x - 48$

Now,make Variable term together and constant term together.

$\sf \longmapsto3x - 24x = - 48 + 20$

$\sf \longmapsto - 21x = - 28$

Negative sign on both sides so ,it gets cancelled.

$\sf \longmapsto \: x = \dfrac{28}{21} = \dfrac{4}{3}$

$\sf \bold{x = \dfrac{4}{3} }$

Check

$\sf \longmapsto 21x = 28$

$\sf \longmapsto21 \times \dfrac{4}{3} = 7 \times 4 = 28$

Answer 2

Answer:

❀ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ:

x−

3

5

=2x−4

\sf \longmapsto \dfrac{x}{4} - \dfrac{5}{3} = 2x - 4⟼

4

x

−

3

5

=2x−4

Now, we take LCM of 4 and 3

4=2×2

3=1×3

LCM of 4 & 3=12

\sf \longmapsto \dfrac{3x - 4 \times 5}{12} = 2x - 4⟼

12

3x−4×5

=2x−4

\sf \longmapsto \dfrac{3x - 20}{12} = 2x - 4⟼

12

3x−20

=2x−4

Now,cross multiply to both sides

\sf \longmapsto3x - 20 = 12(2x - 4)⟼3x−20=12(2x−4)

Now, expanding the terms

\sf \longmapsto3x - 20 = 24x - 48⟼3x−20=24x−48

Now,make Variable term together and constant term together.

\sf \longmapsto3x - 24x = - 48 + 20⟼3x−24x=−48+20

\sf \longmapsto - 21x = - 28⟼−21x=−28

Negative sign on both sides so ,it gets cancelled.

\sf \longmapsto \: x = \dfrac{28}{21} = \dfrac{4}{3}⟼x=

21

28

=

3

4

\sf \bold{x = \dfrac{4}{3} }x=

3

4

Check

\sf \longmapsto 21x = 28⟼21x=28

\sf \longmapsto21 \times \dfrac{4}{3} = 7 \times 4 = 28⟼21×

3

4

=7×4=28