Question

Solve (1) and (2).........

Answer 1

Hey !




(1) /_ BDC = /_ BAC = 30° [ Angles in the same segment ]


In triangle BCD , the sum of the angles is 180°.


Therefore,



/_ CBD + /_ BCD + /_ BDC = 180°



=> 70° + X° + 30° = 180°




=> X° = 180 - 100°



=> X° = 80°




(2) /_ APB = 90° [ Angels in a semicircle ]



/_ BAP + /_ APB + /_ ABP = 180°



=> /_ BAP + 90° + 35° = 180°



=> /_ BAP = ( 180° - 125° )



=> /_ BAP = 55°



Now, X° = /_ BQP = /_ BAP = 55° [ Angles in the same segment ]


Hence,


X° = 55