Solve 1 by 3 + 5 iota
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Answer:
(3-5i)/34
Step-by-step explanation:
1/(3+5i)
on rationalising the denominator
we get 1/(3+5i) multiply by (3-5i)/(3-5i)
on simplifying we get (3-5i)/9-25(i)^2=(3-5i)/(9+25) i^2=(-1)
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