Question

solve 1 no.
please fast..i need it urgent​

Answer 1

${ (\sqrt{6}) } \: ^{x - 2} = \frac{ { \sqrt{6} }^{x} }{6} = 1$

Thus from the above relation, we get;

${ \sqrt{6} }^{x} = 6 \\ = > x = 2$

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