Question

solve 1/x-3 + 2/x-2 = 8/x ,x is not equal to 0 , 2 , 3​

Answer 1

Answer:

$\frac{X-2 + X-3 }{(X-3)(X-2)}$ = $\frac{8}{x}$

$\frac{2x - 5 }{ x^2 - 2x - 3x + 6}$ = $\frac{8}{x}$

x * ( 2x - 5 ) = 8*(x^2 - 5x + 6 )

2x^3 -5x = 8x^2 - 40x + 48

⇒ 2x^3 - 8x^2+ 40x -5x - 48

⇒2x^3 - 8x^2 + 35x - 48

Answer 2

Answer:

1/ ( x- 3 ) + 2 /( x - 2 ) = 8 / x

[ x - 2 + 2 ( x -3 ) ] / [ ( x - 3 ) ( x- 2 ) ] = 8 / x

[ x - 2 + 2x - 6 ] / ( x^2 - 5x + 6 ) = 8/ x

[ 3x - 8 ] / ( x^2 - 5x + 6 ) = 8/ x

x (  3x - 8 ) = 8 ( x^2 - 5x + 6 )

3x^2 - 8x = 8 x^2 - 40 x + 48

8x^2 - 3 x^2 - 40 x + 8x + 48= 0

5x^2 - 32 x + 48 = 0

x = 4 or 12 / 5 ( answer )

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