Question

solve 11 , 16, 17problem

Answer 1

ANSWER OF QUESTION 11
Let the total number of passengers be $x$. 
Children = $\frac{1}{8}x$
Men = $\frac{2}{5}x$
Women = $(1- \frac{1}{8}- \frac{2}{5})x$
Number of women = 380

Now, in the given equation, solve for $x$. 
$(1- \frac{1}{8}- \frac{2}{5})x = 380$
$( \frac{40-5-16}{40})x = 380$
$( \frac{19}{40})x = 380$
$\frac{19}{40}x = 380$
$\frac{19}{40}x * \frac{40}{19} = 380 * \frac{40}{19}$
$x = 800$
The value of $x$ is 800. 
∴ The total number of passengers in the train is 800. 


ANSWER OF QUESTION 16
Area of rectangle = $12 \frac{7}{4} m^{2} = \frac{55}{4} m^{2}$
Length of rectangle = $\frac{7}{12} m$
Let the breadth of rectangle be $x$ m. 

As we all know, Length × Breadth = Area. 
Now, solve for x in the equation to get the breadth. 
$\frac{7}{12} * x = \frac{55}{4}$
$\frac{7}{12}x = \frac{55}{4}$
$\frac{7}{12}x * \frac{12}{7} = \frac{55}{4} * \frac{12}{7}$
$x = \frac{165}{7}$
∴ The breadth of the rectangle is $\frac{165}{7}m$. 

Finding the perimeter. 
The formula for the perimeter is $2(l+b)$. 
Substitute the values of length and breadth into this formula. 
$2( \frac{7}{12} + \frac{165}{7})$
$= \frac{2029}{42}$
∴ The perimeter of the rectangle is $\frac{2029}{42} m$. 

Sorry friend, I cannot understand question 17. I am able to help you with giving the solutions of questions 11 and 16. Please, don't mind. 

Hope this may help you.