Question

solve......................11th ist and 2part

Answer 1

Hi...☺

Here is your answer...✌

$(i)\: \: \frac{15 {x}^{5} {y}^{ - 2} {z}^{4} }{5 {x}^{3} {y}^{3} {z}^{2} } \\ \\ = 3 {x}^{(5 - 3)} {y}^{ (- 2 - 3)} {z}^{(4 - 2)} \\ \\ = 3 {x}^{2} {y}^{ - 5} {z}^{2} \\ \\ = \frac{3 {x}^{2} z^{2}}{ {y}^{5} } \\ \\ (ii) \: \: \frac{42 {x}^{3} {y}^{2} {z}^{4} }{6x {y}^{2} {z}^{3} } \\ \\ = 7 {x}^{(3 - 1)} {y}^{(2 - 2)} {z}^{(4 - 3)} \\ \\ = 7 {x}^{2} {y}^{0} {z}^{1} \\ \\ = 7 {x}^{2} z \: \: \: \: \: \: \: \: \: ( \: since \: \: {y}^{0} = 1 \: )$