Math, asked by irfanmes1221, 6 months ago

Solve: 12abx2 – (9a2 – 8b2)x - 6ab = 0 using by factorisation method.​

Answers

Answered by iTzSnOw
4

[tex]12abx2−(9a2−8b2)x−6ab=0a=0,b=0

Therefore, the roots are:

x=2×12ab(9a2−8b2)±(9a2−8b2)2+24ab(12ab)=24ab(9a2−8b2)±81a4+64b4−144a2b2+288a2b2

=24ab(9a2−8b2)±(9a2+8b2)2

=24ab(9a2−8b2)±(9a2+8b2)

∴x=24ab9a2×2=4b3aor,x=24ab−8b2×2=3a−2b..

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