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x²+x-(a+2)(a+1)=0
x²+(a+2)x-(a+1)x-(a+2)(a+1)=0
x(x+a+2)-(a+1)(x+a+2)=0
(x-a-1)(x+a+2)=0
so,
x-a-1=0
x=a+1
and,
x+a+2=0
x=-a-2
x²+(a+2)x-(a+1)x-(a+2)(a+1)=0
x(x+a+2)-(a+1)(x+a+2)=0
(x-a-1)(x+a+2)=0
so,
x-a-1=0
x=a+1
and,
x+a+2=0
x=-a-2
sripulijhu:
wowsome..thanks a lot...u have to help me with some more doubts...bdw how did u get to know which approach should be followed
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