Question

solve 16 19 and 20
fast thus is urgent​

Answer 1

Answer:

16.)

Given that,

$\frac{2x}{3} + \frac{x}{4} + \frac{x}{2} = 34$

Now Taking LCM Of (3 ,4,2) which is equal to 12

Now,

$\frac{8x + 3x + 6x}{12} = 34$

$17x = 408$

$x = \frac{408}{17}$

$x = 24$

19.)

Given That,

$10 - 5 (\frac{1 + x}{3} ) + \frac{3x + 1}{5} = 0$

$10 - ( \frac{5 + 5x}{3} ) + \frac{3x + 1}{5} = 0$

Now Taking LCM of 3,5 which is equal to 15

Now,

$\frac{150 - 5(5 + 5x) + 3(3x + 1)}{15} = 0$

$=> 150 - 25 - 25x + 9x + 3 = 0$

$= > 128 - 16x = 0$

$16x = 128$

$x = \frac{128}{16}$

$x = 8$

20.)

Given That,

$\frac{2b + 1}{5} - \frac{b - 1}{3} = 1$

Now taking LCM of (3,5) We get,

$\frac{3(2b + 1) - 5(b - 1)}{15} = 1$

$= > 6b + 3 - 5b + 5= 15$

$= > b + 8= 15$

$= > b = 15 - 8$

$b = 7$

Hence All sums are solved.

Hope its Helpss!!!