Math, asked by khushikumari711089, 3 months ago

Solve 2^2x+3 - 9x2^x + 1 = 0​

Answers

Answered by amitsharma777222999
0

Answer:

2^3*2^2x-9*2^x+1=0

8*2^2x-9*2^x+1=0

let 2^x=y

8y^2-9y+1=0

8y^2-8y-y+1=0

8y(y-1)-1(y-1)=0

(8y-1)(y-1)=0

y=1/8 or y=1

2^x=2^-3 or 2^x=2^0

x=-3 or x=0

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