solve 2/5 x²-x- 3/5=0
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Answered by
2
2/5 x^2 -x-3/5=0
2x^2-5x-3 divide by 5 =0
2x^2 -5x -3 =0 *5
2x^2 -5x -3 =0
2x^2-2x-3x-3=0
-2x(x+1)-3(x+1)=0
(x+1)(-2x-3)=0
but i m not confirmed
2x^2-5x-3 divide by 5 =0
2x^2 -5x -3 =0 *5
2x^2 -5x -3 =0
2x^2-2x-3x-3=0
-2x(x+1)-3(x+1)=0
(x+1)(-2x-3)=0
but i m not confirmed
mysticd:
it is wrong . plz check.
ok
Answered by
10
Hi ,
2/5 x² - x - 3/5 = 0
multiply each term with 5, we get
2x² - 5x - 3 = 0
splitting the middle term
2x² - 6x + x - 3 = 0
2x ( x - 3 ) + 1 ( x - 3 ) = 0
( x - 3 ) ( 2x + 1 ) = 0
Therefore ,
x - 3 = 0 or 2 x + 1 = 0
x = 3 or x = ( -1/2 )
I hope this helps you.
:)
2/5 x² - x - 3/5 = 0
multiply each term with 5, we get
2x² - 5x - 3 = 0
splitting the middle term
2x² - 6x + x - 3 = 0
2x ( x - 3 ) + 1 ( x - 3 ) = 0
( x - 3 ) ( 2x + 1 ) = 0
Therefore ,
x - 3 = 0 or 2 x + 1 = 0
x = 3 or x = ( -1/2 )
I hope this helps you.
:)
:)
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