Question

Solve: 2 integer 2 upon 3 and 3 integer 1 upon 2

Answer 1

Answer:

62/6

Step-by-step explanation:

I hope this answer is correct

Answer 2

Note: the given question is incomplete as its should be as follows:

Solve, 2 integer $\frac{2}{3}$ + 3 integer $\frac{1}{2} +\frac{1}{6}$.

Given: 2 integer $\frac{2}{3}$ + 3 integer $\frac{1}{2} +\frac{1}{6}$.

To find: the solution of the given expression.

Solution:

Simplify the given expression.

2 integer $\frac{2}{3}$ + 3 integer $\frac{1}{2} +\frac{1}{6}$,

$\[2\frac{2}{3} + 3\frac{1}{2} + \frac{1}{6} = \frac{{2 \times 2}}{3} + \frac{{3 \times 1}}{2} + \frac{1}{6}\]$

                   $\[ = \frac{4}{3} + \frac{3}{2} + \frac{1}{6}\]$

                   $\[ = \frac{{4 \times 2 + 3 \times 3 + 1}}{6}\]$

                    $\[ = \frac{{8 + 9 + 1}}{6}\]$

                   $\[ = \frac{{18}}{6}\]$

                   $\[ = 3\]$

Hence, the solution of the given expression, 2 integer $\frac{2}{3}$ + 3 integer $\frac{1}{2} +\frac{1}{6}$ is 3.