Math, asked by rezzak, 1 year ago

solve. 2^n+2^n-1/2^n+1-2^n

Answers

Answered by mysticd
4
Hi ,

( 2^n + 2^n-1 ) / ( 2^n+1 - 2^n )

= [ 2^n + ( 2^n / 2 ) ] / [ 2^n × 2 - 2^n ]

= { 2^n [ 1 + 1/2 ] } / { 2^n [ 2 - 1 ]

= ( 1 + 1/2 ) / 1

= 3/2

I hope this helps you.

: )
Answered by sushant2505
3
Hi...☺

Here is your answer...✌

  \frac{{2}^{n}  +  {2}^{n - 1} }{  {2}^{n + 1}  -  {2}^{n} }   \\  \\  =    \frac{{2}^{n}  +  {2}^{n}  \times  {2}^{ - 1} }{  {2}^{n }  \times  {2}^{1}  -  {2}^{n} }   \\   \\  =  \frac{  {2}^{n}(1 +  {2}^{ - 1} ) }{ {2}^{n} (2 - 1)}  \\  \\  =  \frac{1 +  \frac{1}{2} }{1}  =  \frac{2 + 1}{2}  \\  \\  =  \frac{3}{2}
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