solve. 2^n+2^n-1/2^n+1-2^n
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Answered by
4
Hi ,
( 2^n + 2^n-1 ) / ( 2^n+1 - 2^n )
= [ 2^n + ( 2^n / 2 ) ] / [ 2^n × 2 - 2^n ]
= { 2^n [ 1 + 1/2 ] } / { 2^n [ 2 - 1 ]
= ( 1 + 1/2 ) / 1
= 3/2
I hope this helps you.
: )
( 2^n + 2^n-1 ) / ( 2^n+1 - 2^n )
= [ 2^n + ( 2^n / 2 ) ] / [ 2^n × 2 - 2^n ]
= { 2^n [ 1 + 1/2 ] } / { 2^n [ 2 - 1 ]
= ( 1 + 1/2 ) / 1
= 3/2
I hope this helps you.
: )
Answered by
3
Hi...☺
Here is your answer...✌
Here is your answer...✌
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