solve 2 problem with solution plz with steps
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x^3-y^3=(x-y)(x^2+y^2+xy).....................1
A/Q,
x/y+y/x=-1
or x^2+y^2/xy=-1
or x^2+y^2=-xy
or x^2+y^2+xy=0
from equation 1
x^3-y^3=(x-y)(x^2+y^2+xy)
=(x-y)×0
=0 answer
A/Q,
x/y+y/x=-1
or x^2+y^2/xy=-1
or x^2+y^2=-xy
or x^2+y^2+xy=0
from equation 1
x^3-y^3=(x-y)(x^2+y^2+xy)
=(x-y)×0
=0 answer
khushikumari11:
please mark me as brainlist ☺☺
no
why is it wrong
or I not defined it clearly
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