Math, asked by ananyajgupta, 7 months ago

solve: [2^((sq.root of (log of x base 2))-2)]+[2^(-(sq.root of (log of x base 2))-2)] =1

Answers

Answered by prashmitiwaru
0

Answer:

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Answered by pareekbajrang2000
1

Answer:

solve: [2^((sq.root of (log of x base 2))-2)]+[2^(-(sq.root of (log of x base 2))-2)] =1

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