solve 2 tan inverse (sin x) is equal to tan inverse ( 2 sec x)
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Answered by
63
We have, 2 tan−1(sinx) = tan−1(2 sec x)
Now, using 2tan−1(x) = tan−1( 2 x/1-x^2)
So, tan−1(2 sin (x)/1-sin^2 (x) ) = tan−1( 2 sec (x) )
or 2 sin (x)/cos^2 (x) = 2/cos (x)
{ Using sec x = 1/cos (x) and 1 - sin^2 (x) = cos^2 (x) }
So, Sin (x)/Cos (x) = 1
or tan (x) = 1
or x = π/4
Now, using 2tan−1(x) = tan−1( 2 x/1-x^2)
So, tan−1(2 sin (x)/1-sin^2 (x) ) = tan−1( 2 sec (x) )
or 2 sin (x)/cos^2 (x) = 2/cos (x)
{ Using sec x = 1/cos (x) and 1 - sin^2 (x) = cos^2 (x) }
So, Sin (x)/Cos (x) = 1
or tan (x) = 1
or x = π/4
Answered by
13
Answer:
Step-by-step explanation:
We have, 2 tan−1(sinx) = tan−1(2 sec x)
Now, using 2tan−1(x) = tan−1( 2 x/1-x^2)
So, tan−1(2 sin (x)/1-sin^2 (x) ) = tan−1( 2 sec (x) )
or 2 sin (x)/cos^2 (x) = 2/cos (x)
{ Using sec x = 1/cos (x) and 1 - sin^2 (x) = cos^2 (x) }
So, Sin (x)/Cos (x) = 1
or tan (x) = 1
or x = π/4
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