solve ; 2^x+1 + 4^x = 8
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Step-by-step explanation:
I am assuming that the equation is 4x - 2x+1 - 8 = 0
4x - 2(2x) - 8 = 0
(2x)2 - 2(2x) - 8 = 0
Let u = 2x. Then the equation becomes u2 - 2u - 8 = 0
(u - 4)(u + 2) = 0
u = 4 or u = -2
So, 2x = 4 or 2x = -2
Since 2x is positive for all x, we can disregard the equation 2x = -2.
Therefore, 2x = 4
2x = 22 x = 2
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