Question

Solve:
2/x + 2/3y = 1/6 and 3/x + 2/y = 0
hence find'm'for which y=mx -4
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Answer 1

Answer:

m = 0 , x = 6 and y = -4

Step-by-step explanation:

2/x + 2/3y = 1/6

3/x + 2/y = 0

put 1/x = a and 1/y = b

2a + 2b/3 = 1/6 -------(1)

3a + 2b = 0 -------(2)

multiply by 3 in eq 1 and 2 in eq 2

3(2a + 2b/3 = 1/6)

2(3a + 2b = 0)

6a + 2b = 1/2 --------(3)

6a + 4b = 0 --------(4)

subtract eq 3 and 4

6a + 2b = 1/2

6a + 4b = 0

- - -

-2b = 1/2

b = -1/4

put b in eq 2

3a + 2b = 0

3a + 2(-1/4) = 0

3a - 1/2 = 0

3a = 1/2

a = 1/6

1/x = a and 1/y = b

1/x = 1/6 and 1/y = -1/4

x = 6 and y = -4

now, y = mx - 4

-4 = m(6) - 4

-4 + 4 = 6m

0 = 6m

m = 0