solve 2^x+3 = 4^x-1 find value of x
Answers
Answered by
2
Answer:
5.
Step-by-step explanation:
⇒ 2^( x + 3 ) = 4^( x - 1 )
⇒ 2^( x + 3 ) = ( 2^2 )^( x - 1 )
⇒ 2^( x + 3 ) = 2^{ 2( x - 1 ) }
⇒ 2^( x + 3 ) = 2^( 2x - 2 )
Powers of two, both sides, must be equal.
⇒ x + 3 = 2x - 2
⇒ 3 + 2 = 2x - x
⇒ 5 = x
Hence the required value of x is 5.
Few terms used here :
4 = 2^2 { in 2nd step, RHS }
( a^n )^m = a^( nm ) { in 3nd step, RHS }
Similar questions