Question

Solve 2/x+3/y=13 5/x-4/y=-2 by substitution method

Answer 1

Step-by-step explanation:

Given Equations Reducible to a Pair of Linear Equations in two variables :

2/x + 3/y = 13 ----(1)

5/x - 4/y = -2 ------(2)

If we substitute 1/x =a and1/y=b,we get the following pair of linear equations:

2a+3b=13-----(3)

5a-4b=-2-----(4)

Coefficients of bare 3 and 4 and

their LCM is 12.

Using the limination method.

Equation(3)×48a+12b=52

Equation(4)×315a-12b=-6

'b' terms have opposite sign ,so we add the two equations.

23a=46

=>a=46/23

=>a=2

Substitute the value of an equation (3), we get

=>2×2+3b=13

=>4+3b=13

=>3b=13-4

=>3b=9

=>b=9/3

=>b=3

But1/x=a=2=>x=1/2

1/y=b=3=>y=1/3

Answer 2

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