Question

solve =2/x +3/y=13 ,5/x-4/y= -2

plz answer the question​

Answer 1

Answer:

Given that ,

suppose 1/x = A and 1/y = B

2A +3B =13 .................(1)

5A - 4B = -2 .................(2)

equation ( 1 ) we get ,. 2A = 13 - 3B

A = 13 - 3 B /2

putting the value of (A ) in equation (2) we get ,

5(13 -3B /2 ) - 4B = -2

= 65 - 15B - 8B = -4

= -23 B = -4 -65 = 69

B = 69/23 = 3 B = 3

A = 13 - 3B / 2 = 13 - 3 ×3 / 2 = 13 - 9 / 2 = 4/2 A = 2

1/x =A

x= 1/A

1/y = B = y = 1/B

x = 1/A = 1/2 y = 1/B = 1/3

hence , x = 1/2 and y = 1/3

Answer 2

2/x +3/y=13 ,5/x-4/y= -2

let 1/x = u and 1/y = v

2u+3v = 13 ..........1

5u-4v = -2 .............2

form eq 1

u= 13-3v /2

put u in eq 2

5(13-3v/2) -4v = -2

65/2 - 15v/2 -4v = -2

-15v/2 -4v = -2 - 65/2

-15v-8v / 2 = -4 -65 / 2

-23v = -69

v= 2

put v=2 in u= 13-3v / 2

u= 13-3×2 /2 = 13-6 / 2 = 7/2

for x and y

1/x = u => x= 2/7

1/y = v => y= 1/2