Question

solve( 2*x-5)/(2x-3)=(3x-1)/(3x+3) . Find the value of x.

Answer 1

$\frac{2x - 5}{2x - 3} = \frac{3x - 1}{3x + 3} \\ \\ \bf \: On \: cross \: multiplying \: we \: get\\ \\ (2x - 5)(3x + 3) = (3x - 1)(2x - 3) \\ \\ 6 {x}^{2} + 6x - 15x - 15 = 6 {x}^{2} - 9x - 2x + 3 \\ \\ 6 {x}^{2} - 9x - 15 = 6 {x}^{2} - 11x + 3 \\ \\ 6 {x}^{2} - 6 {x}^{2} - 9x + 11x - 15 - 3 = 0 \\ \\ 2x - 18 = 0 \\ \\ 2x = 18 \\ \\ x = \frac{18}{2} \\ \\ x = 9$

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