Question

solve 2(x*x)+3x-90.

Answer 1

Answer:

2x^2+3X-90

Step-by-step explanation:

2*X*X+3*X-90

Answer 2

Answer:

-15/2 and 6 are the zeroes for the given problem

Step-by-step explanation:

Given that:2(x*x)+3x-90

2(x*x)+3x-90

2(x*x)+3x-90=>2x^2+3x-90

2(x*x)+3x-90=>2x^2+3x-90=>2x^2-12x+15x-90

2(x*x)+3x-90=>2x^2+3x-90=>2x^2-12x+15x-90=>2x(x-6)+15(x-6)

2(x*x)+3x-90=>2x^2+3x-90=>2x^2-12x+15x-90=>2x(x-6)+15(x-6)=>(2x+15)(x-6)

now for solving 2x+15=0 or x-6=0

=>x=-15/2 or x=6

values of x= -15/2 and 6

therefore zeroes of the given polynomial are -15/2 and 6